[VB]Base64加密解密模块
2010-07-15 01:41:52 作者：未知 来源：未知 浏览次数： 评论 0 条
以下为类模块Class1.cls
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Public Function Base64Encode(ByVal InStr1 As String) As String '¼ÓÃÜ
Dim mInByte(3) As Byte, mOutByte(4) As Byte
Dim myByte As Byte
Dim i As Integer, LenArray As Integer, j As Integer
Dim myBArray() As Byte
Dim OutStr1 As String
myBArray() = StrConv(InStr1, vbFromUnicode)
LenArray = UBound(myBArray) + 1
For i = 0 To LenArray Step 3
If LenArray - i = 0 Then
Exit For
End If
If LenArray - i = 2 Then
mInByte(0) = myBArray(i)
mInByte(1) = myBArray(i + 1)
Base64EncodeByte mInByte, mOutByte, 2
ElseIf LenArray - i = 1 Then
mInByte(0) = myBArray(i)
Base64EncodeByte mInByte, mOutByte, 1
Else
mInByte(0) = myBArray(i)
mInByte(1) = myBArray(i + 1)
mInByte(2) = myBArray(i + 2)
Base64EncodeByte mInByte, mOutByte, 3
End If
For j = 0 To 3
OutStr1 = OutStr1 & Chr(mOutByte(j))
Next j
Next i
Base64Encode = OutStr1
End Function
Private Sub Base64EncodeByte(mInByte() As Byte, mOutByte() As Byte, Num As Integer)
Dim tByte As Byte
Dim i As Integer
If Num = 1 Then
mInByte(1) = 0
mInByte(2) = 0
ElseIf Num = 2 Then
mInByte(2) = 0
End If
tByte = mInByte(0) And &HFC
mOutByte(0) = tByte / 4
tByte = ((mInByte(0) And &H3) * 16) + (mInByte(1) And &HF0) / 16
mOutByte(1) = tByte
tByte = ((mInByte(1) And &HF) * 4) + ((mInByte(2) And &HC0) / 64)
mOutByte(2) = tByte
tByte = (mInByte(2) And &H3F)
mOutByte(3) = tByte
For i = 0 To 3
If mOutByte(i) >= 0 And mOutByte(i) <= 25 Then
mOutByte(i) = mOutByte(i) + Asc("A")
ElseIf mOutByte(i) >= 26 And mOutByte(i) <= 51 Then
mOutByte(i) = mOutByte(i) - 26 + Asc("a")
ElseIf mOutByte(i) >= 52 And mOutByte(i) <= 61 Then
mOutByte(i) = mOutByte(i) - 52 + Asc("0")
ElseIf mOutByte(i) = 62 Then
mOutByte(i) = Asc("+")
Else
mOutByte(i) = Asc("/")
End If
Next i
If Num = 1 Then
mOutByte(2) = Asc("=")
mOutByte(3) = Asc("=")
ElseIf Num = 2 Then
mOutByte(3) = Asc("=")
End If
End Sub
Public Function Base64Decode(ByVal InStr1 As String) As String '½âÃÜ
Dim mInByte(4) As Byte, mOutByte(3) As Byte
Dim i As Integer, LenArray As Integer, j As Integer
Dim myBArray() As Byte
Dim OutStr1 As String
Dim tmpArray() As Byte
myBArray() = StrConv(InStr1, vbFromUnicode)
LenArray = UBound(myBArray)
ReDim tmpArray(((LenArray + 1) / 4) * 3)
j = 0
For i = 0 To LenArray Step 4
If LenArray - i = 0 Then
Exit For
Else
mInByte(0) = myBArray(i)
mInByte(1) = myBArray(i + 1)
mInByte(2) = myBArray(i + 2)
mInByte(3) = myBArray(i + 3)
Base64DecodeByte mInByte, mOutByte, 4
End If
tmpArray(j * 3) = mOutByte(0)
tmpArray(j * 3 + 1) = mOutByte(1)
tmpArray(j * 3 + 2) = mOutByte(2)
j = j + 1
Next i
Base64Decode = BinaryToString(tmpArray)
End Function
Private Sub Base64DecodeByte(mInByte() As Byte, mOutByte() As Byte, ByteNum As Integer)
Dim tByte As Byte
Dim i As Integer
ByteNum = 0
For i = 0 To 3
If mInByte(i) >= Asc("A") And mInByte(i) <= Asc("Z") Then
mInByte(i) = mInByte(i) - Asc("A")
ElseIf mInByte(i) >= Asc("a") And mInByte(i) <= Asc("z") Then
mInByte(i) = mInByte(i) - Asc("a") + 26
ElseIf mInByte(i) >= Asc("0") And mInByte(i) <= Asc("9") Then
mInByte(i) = mInByte(i) - Asc("0") + 52
ElseIf mInByte(i) = Asc("+") Then
mInByte(i) = 62
ElseIf mInByte(i) = Asc("/") Then
mInByte(i) = 63
Else '"="
ByteNum = ByteNum + 1
mInByte(i) = 0
End If
Next i
'È¡Ç°Áùλ
tByte = (mInByte(0) And &H3F) * 4 + (mInByte(1) And &H30) / 16
'0µÄÁùλºÍ1µÄÇ°Á½Î»
mOutByte(0) = tByte
tByte = (mInByte(1) And &HF) * 16 + (mInByte(2) And &H3C) / 4
'1µÄºóËÄλºÍ2µÄÇ°ËÄλ
mOutByte(1) = tByte
tByte = (mInByte(2) And &H3) * 64 + (mInByte(3) And &H3F)
mOutByte(2) = tByte
'2µÄºóÁ½Î»ºÍ3µÄÁùλ
End Sub
Private Function BinaryToString(ByVal BinaryStr As Variant) As String '¶þ½øÖÆת»»Îª×Ö·û´®
Dim lnglen As Long
Dim tmpBin As Variant
Dim strC As String
Dim skipflag As Long
Dim i As Long
skipflag = 0
strC = ""
If Not IsNull(BinaryStr) Then
lnglen = LenB(BinaryStr)
For i = 1 To lnglen
If skipflag = 0 Then
tmpBin = MidB(BinaryStr, i, 1)
If AscB(tmpBin) > 127 Then
strC = strC & Chr(AscW(MidB(BinaryStr, i + 1, 1) & tmpBin))
skipflag = 1
Else
strC = strC & Chr(AscB(tmpBin))
End If
Else
skipflag = 0
End If
Next
End If
BinaryToString = strC
End Function
Private Function StringToBinary(ByVal VarString As String) As Variant '×Ö·û´®×ª³É¶þ½øÖÆ
Dim strBin As Variant
Dim varchar As Variant
Dim varasc As Long
Dim varlow, varhigh
Dim i As Long
strBin = ""
For i = 1 To Len(VarString)
varchar = Mid(VarString, i, 1)
varasc = Asc(varchar)
If varasc < 0 Then
varasc = varasc + 65535
End If
If varasc > 255 Then
varlow = Left(Hex(Asc(varchar)), 2)
varhigh = Right(Hex(Asc(varchar)), 2)
strBin = strBin & ChrB("&H" & varlow) & ChrB("&H" & varhigh)
Else
strBin = strBin & ChrB(AscB(varchar))
End If
Next
StringToBinary = strBin
End Function
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以上。
经测试这个竟然能加密多行文本以及格式。。解密出来以后格式都和原来的一样。。
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